Answer:
factors are : (3x+2)(3x-5)(x²-5)(x+3)
Step-by-step explanation:
given : [tex]9x^{5} +18x^{4} -82x^{3} -120x^{2}+185x+150 [/tex]
( x + 3 ) is a factor of the following, can be found if " -3 " is replaced with x and put into equation and output is 0.
[tex]9(-3)^{5} +18(-3)^{4} -82(-3)^{3} -120(-3)^{2}+185(-3)+150 [/tex] = 0
as a result proved, ( x + 3 ) is a factor.
then divide, the following using ( x + 3 )
the answer should come = (3x+2)(3x-5)(x²-5)
so the factors are : (3x+2)(3x-5)(x²-5)(x+3)
