Answer:
Option B
The answer is 15
Step-by-step explanation:
Given;
- Two points A(2, 10) and C(14, 1)
To Find;
- The distance between A(2, 10) and C(14, 1)
Formula;
AC = √[(x₂ – x₁)² + (y₂ – y₁)²]
Now,
x₁ = 2
x₂ = 14
y₁ = 10
y₂ = 1
AC = √[(x₂ – x₁)² + (y₂ – y₁)²]
AC = √[(14 – 2)² + (1 – 10)²]
AC = √[(12)² + (-9)²]
AC = √(144 + 81)
AC = √225
AC = 15 units
Thus, The distance between A(2, 10) and C(14, 1) is 15 units
-TheUnknownScientist 72
