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Find the equation of the line that contains the given point and is perpendicular to the given line. Write the equation in slope-intercept form, if possible, (6,2);y=-3x-3

Find the equation of the line that contains the given point and is perpendicular to the given line Write the equation in slopeintercept form if possible 62y3x3 class=

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iciclepiano18

Answer:

[tex]y=\frac{1}{3}x[/tex]

Step-by-step explanation:

We need to find a line perpendicular to the given line. Let's first find the slope. If the line is perpendicular, it's slope is the negative reciprocal of the given line:

[tex]\frac{1}{3}x[/tex]

Now that we know the slope, we can plug in the given points to solve for the y-intercept.

[tex]y=\frac{1}{3}x+b\\ 2=\frac{1}{3}*6+b\\ 2=2+b\\ b=0[/tex]

Therefore the equation of the line is:

[tex]y=\frac{1}{3}x[/tex]

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