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A company of cellular phones can sell 30 units per day at Php 6,000 each. Then, they found out that they can sell 10 more cell phone units per day for each Php 100 decrease in price. As a marketing manager you're going to present the maximum sale and the price per cell phone unit to reach the maximum sale through a graph. Quadratic Function​

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MrRoyal

Quadratic functions are functions that have a highest exponent of 2

  • The quadratic function is [tex]Q(x) = -1000x^2 + 57000x + 180000[/tex]
  • The maximum sale is 114

How to determine the quadratic function

The initial parameters are:

  • Sales = 30 units daily
  • Cost = Php 6000

When 10 units are added and the price decreases; the parameters become:

  • Sales = 30 + 10x units daily
  • Cost = Php 6000 -100x

So, the quadratic function is:

[tex]Q(x) = (30 + 10x)(6000 - 100x)[/tex]

[tex]Q(x) = -1000x^2 + 57000x + 180000[/tex]

How to determine the maximum sale and price

We have:

[tex]Q(x) = -1000x^2 + 57000x + 180000[/tex]

Differentiate

[tex]Q'(x) = -2000x + 57000[/tex]

Set to 0

[tex]-2000x + 57000 = 0[/tex]

Divide through by -2000

[tex]x - 114 = 0[/tex]

Solve for x

[tex]x = 114[/tex]

Hence, the maximum sale is 114

Read more about quadratic functions at:

https://brainly.com/question/11631534