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Consider the equations below. (1) Ca(s) CO2(g) 1 2 O2(g) → CaCO3(s) (2) 2Ca(s) O2(g) → 2CaO(s) How should you manipulate these equations so that they produce the equation below when added? Check all that apply. CaO(s) CO2(g) → CaCO3(s) reverse the direction of equation (2) multiply equation (1) by 3 multiply equation (2) by 1/2.

Respuesta :

The final equation is obtained by reversing equation 2 and multiplying it by 1/2. Thus, option A and C are correct.

The given equations are:

[tex]\rm Ca\;+\;CO_2\;+\;1/2\;O_2\;\rightarrow\;CaCO_3[/tex]

[tex]\rm 2\;Ca\;+\;O_2\;\rightarrow\;2\;CaO[/tex]

The final equation to be obtained are:

[tex]\rm CaO\;+\;CO_2\;\rightarrow\;CaCO_3[/tex]

Computation for the final equation

The final reaction is obtained with the CaO as the product. The CaO as product is obtained by reversing equation 2.

The half of equation 2 will give the final equation.

Thus, the final equation is obtained by reversing equation 2 and multiplying it by 1/2. Thus, option A and C are correct.

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