Pls help me solve the problem

Answer:
The 54th term is -855
Step-by-step explanation:
Since the sequence is arithmetic, then we have to use the rule of the nth term
[tex]a_{n}=a+(n-1)d[/tex]
a is the first term
d is the common difference
n is the position
The given sequence is -7, -23, -39
a=-7
d=-23-(-7)=-23+6=-16
We need to find the 54th term
n=54
Substitute them in the rule
[tex]a_{54}=-7+(54-10)(-16) [/tex]
Solve it:
[tex]a_{54}=-7+(53)(-16)\\ a_{54}=-7-848\\ a_{54}=-855 [/tex]
The 54th term is -855
Answer:
The characteristic of an arithmetic sequence is:
This difference between consecutive terms is called common difference and is denoted by (d)
(finding the common difference)
As stated above, the common difference is the difference between consecutive terms and, thus, will be found out by subtracting any two consecutive terms.
-7 and -23 are two consecutive terms in the sequence!
Subtracting (-7) from (-23):
[tex] \implies \mathsf{d = - 23 - ( - 7)}[/tex]
[tex] \implies \mathsf{d = - 23 + 7}[/tex]
[tex] \implies \mathsf{ \underline{d = -16}}[/tex]
(Finding the nth term)
The formula used for finding the nth term of an arithmetic sequence is:
[tex] \boxed{ \mathsf{a _{n} = a + (n - 1)d }}[/tex]
Here,
The question asks us to find the 54th term of the sequence.
Substituting 54 for n:
[tex] \implies \mathsf{a _{54} = a + (54 - 1)d }[/tex]
substituting -7 for a and -16 for d
[tex] \implies \mathsf{a _{54} = - 7+ (54 - 1)( - 16)}[/tex]
[tex] \implies \mathsf{a _{54} = - 7+ (53)( - 16)}[/tex]
[tex] \implies \mathsf{a _{54} = - 7 - 848}[/tex]
[tex] \implies \mathsf{ \underline{a _{54} = - 855}}[/tex]
The 54th term of the sequence is -855.
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Learn more about nth term of an AP here:
https://brainly.com/question/16613594
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Hope this helps!