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Porter takes a sheet of paper and makes a diagonal cut from one corner to the opposite corner, making two triangles. The cut he makes is 9 inches long, and the length of the paper is 7 inches. What is the paper's width? If necessary, round to the nearest tenth.

Respuesta :

akposevictor

The width of the rectangular paper is: 5.7 inches.

Diagonal of a Rectangle

Diagonal of a rectangle can be found using the Pythagorean Theorem, such as if c is the diagonal, a is the length, and b is the width, therefore, c² = a² + b².

  • Thus, the cut made from one corner to another is the diagonal of the rectangular shaped paper = 9 inches.
  • Length of the paper = 7 inches.

Find the width using the Pythagorean Theorem:

width² = 9² - 7²

width² = 32

width = √32

width = 5.7 inches.

Thus, the width of the rectangular paper is: 5.7 inches.

Learn more about diagonal of a rectangle on:

https://brainly.com/question/17117320

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