A light plane travels a distance of 150 m along a runway before takeoff. Find the work done by the plane engine if it is applying a force of 13500 N?

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Wolfyy

Answer:

2,025,000J

Explanation:

We can use the formula [ w = fd ] to solve.

= (150)(13500)

= 2025000J

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The work done by the engine depends on the applied force and displacement along the runway. The work done by the engine is 2025000 Joules.

What is work?

The work done by an object is defined as the measure of energy transfer that occurs when the object is moved over a distance by an external force is applied in the direction of the displacement.

Given that the force applied on the engine is 13500 N and the distance of 150 m along a runway before takeoff.

The work done by the engine is calculated as given below.

[tex]W = Fd[/tex]

Where W is the work done and F is the force. d is the distance along the runway.

[tex]W = 13500 \times 150[/tex]

[tex]W = 2025000 \;\rm J[/tex]

Hence we can conclude that the work done by the engine is 2025000 Joules.

To know more about the work, follow the link given below.

https://brainly.com/question/3902440.