The acceleration of the student-bicycle system is 5 m/s².
The net force on the student-bicycle system
The net force on the student-bicycle system is calculated as follows;
[tex]F_{net} = F_n - F_f\\\\F_{net} = 500 - 250\\\\F_{net} = 250 \ N[/tex]
The mass of the student-bicycle system
[tex]m = \frac{W}{g} \\\\m = \frac{500}{10} \\\\m = 50 \ kg[/tex]
The acceleration of the student-bicycle system
[tex]a = \frac{F_{net}}{m} \\\\a = \frac{250 \ N}{50 \ kg} \\\\a = 5 \ m/s^2[/tex]
The complete question is below:
A student rides a bicycle in a circle at a constant speed. What is the acceleration of the student-bicycle system?
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