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A tank is half full of oil that has a density of 900 kg/m3. Find the work w (in j) required to pump the oil out of the spout. (use 9. 8 m/s2 for g. Round your answer to the nearest whole number. ).

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asuwafohjames

The work required to pump out the spout is 31904409.6 J

What is work?

This can be defined as the product of force and distance.

To calculate the work required to pump the oil out of the spout, we use the formula below.

Assuming the correct question is

Question: A tank is half full of oil that has a density of 900 kg/m³. Find the work W (in J) required to pump the oil out of the spout. (Use 9.8 m/s² for g. Round your answer to the nearest whole number.)

(A spherical tank is given. The tank has a radius of 12 m and spouts coming out of the top with a height of 4 m.)

Formula:

  • W = Dπr²gH²/2............... Equation 1

Where:

  • W = Work required to pump the oil out of the spout.
  • D = Density of the oil
  • R = Radius of the base of the tank
  • H = Height of the tank
  • g = acceleration due to gravity.

From the question,

Given:

  • D = 900 kg/m³,
  • r = 12 m
  • H = 4 m
  • g = 9.8 m/s²
  • π = 3.14

Substitute these values into equation 1

  • W = 900(3.14)(12²)(4²)(9.8)/2
  • W = 31904409.6 J

Hence, The work required to pump out the spout is 31904409.6 J

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