contestada

Consider a 50-N weight suspended by two wires as shown in the accompanying figure. If the magnitude of vector F, is
38 N, find angle a and the magnitude of vector F2.

Respuesta :

The magnitude of vector F2 is 12 N and the value of the missing angle a is 16.2⁰.

The magnitude of vector F2

The sum of the upward forces is equal to sum of the downward forces.

F₁ + F₂ = F₃

F₂ = F₃ - F₁

F₂ = 50 N - 38 N

F₂ = 12 N

The missing angle a

The value of the missing angle is determined by applying sine rule.

[tex]\frac{F_2}{sin (a)} = \frac{F_1}{sin(62)} \\\\\frac{12}{sin (a)} = \frac{38}{sin(62)} \\\\sin(a) = \frac{12 \times sin(62)}{38} \\\\sin(a) = 0.279\\\\a = sin^{-1} (0.279)\\\\a = 16.2 \ ^0[/tex]

Thus, the magnitude of vector F2 is 12 N and the value of the missing angle a is 16.2⁰.

Learn more about concurrent forces here: https://brainly.com/question/20165540

Ver imagen onyebuchinnaji