Answer:
[tex]-\frac{x^3}{27y^6} [/tex]
Step-by-step explanation:
One rule of exponents: anything to the zero-th power is 1
This turns the expression into just:
[tex](\frac{1}{-3x^{-1}y^2} )^3[/tex]
Then, we can utilize another rule that states: any negative exponents can be expressed on the opposite side of a fraction, but with a positive exponent. Using this rule, the expression becomes:
[tex](-\frac{x}{3y^2} )^3[/tex]
After this, and cubing the expression (when taking exponents to a certain power, the exponents are multiplied and constants are raised to the power:
[tex]-\frac{x^3}{27y^6} [/tex]
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