4. What is the perimeter of the regular octagon below? Round
to the nearest hundredth.

Explanation:
Let's use the distance formula to find the distance from A to B (aka the length of side AB).
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\ d = \sqrt{(-4-(-1))^2 + (1-(-1))^2}\\\\ d = \sqrt{(-4+1)^2 + (1+1)^2}\\\\ d = \sqrt{(-3)^2 + (2)^2}\\\\ d = \sqrt{9 + 4}\\\\ d = \sqrt{13}\\\\ d \approx 3.60555128\\\\ d \approx 3.6056[/tex]
Side AB is roughly 3.6056 units long.
In any regular polygon, the sides are the same length.
Because of that, this regular octagon has 8 sides of roughly 3.6056 units each.
The perimeter is 8*3.6056 = 28.8448 approximately. This rounds to 28.84 when rounding to the nearest hundredth (aka 2 decimal places).