Respuesta :
We have that the gravitational potential energy effect on the system is mathematically given as
- The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.
Option C
From the question we are told
- The objects are initially at rest, and the mass of object y is greater than the mass of object x.
- As object y falls, how does the gravitational potential energy of the object x-object y-earth system change? all frictional forces are considered to be negligible.
Centre of mass
Due to reduce in top of Y, doable strength will limit and due to amplify in peak of X, achievable power will increase.
Now, PE = mgh.
Generally the equation for the Velocity of centre of mass is mathematically given as
[tex]V =\frac{ m1v1 + m2v2}{ m1 + m2}\\\\Therefore \\\\V =\frac{ (m1 - m2) v}{ m1 + m2}[/tex]
Hence, V is positive as m1 > m2
Therefore
- centre of mass of system moves downwards.
The conclusion
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.
Option C
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Complete Question
Objects X and Y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an Atwood’s machine, as shown in the figure.
The objects are initially at rest, and the mass of Object Y is greater than the mass of Object X. As Object Y falls, how does the gravitational potential energy of the Object Y-Object Y-Earth system change? All frictional forces are considered to be negligible.
a
The gravitational potential energy increases because the center of mass of Object X and Object Y moves upward.
b
The gravitational potential energy increases because the center of mass of Object X and Object Y moves downward.
c
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.
d
The gravitational potential energy decreases because the center of mass of Object X and Object Y moves upward.