Answer:
[tex]\frac{1}{64} [/tex]
[tex]\frac{1}{8} [/tex]
1
8
64
Step-by-step explanation:
Basically, you plug the x value that is in the left column into the x in the equation f(x)=8ˣ.
For -2, it would be f(-2)=[tex]8^{-2} [/tex].
Solve: any number with a negative exponent is 1/[that number], so this would be 1/([tex]8^{2} [/tex])
= 1/64 <- because 8*8=64
*The f(-2) or f(x) (or f([any number]) )is just showing the output of the function 8ˣ.
For -1, it would be f(-1)=[tex]8^{-1} [/tex].
Solve: any number with a negative exponent is 1/[that number], so this would be 1/([tex]8^{1} [/tex])
= 1/8 <- because any number to the first power is just that number.
For 0, it would be f(0)=[tex]8^{0} [/tex].
Solve: any number with an exponent that is zero is just 1
[tex]8^{0} [/tex] = 1
For -1, it would be f(1)=[tex]8^{1} [/tex].
Solve: [tex]8^{1} [/tex] = 8
For -2, it would be f(2)=[tex]8^{2} [/tex].
Solve: [tex]8^{2} [/tex]
= 64 <- because 8*8=64
