Answer:
The limiting reagent is FeBr3.
Explanation:
from the reaction, you find a ratio between FeBr3 and Fe2(CrO4)3.
This ratio is 2 moles of FeBr3 reacts and forms 1 mole of Fe2(CrO4)3.
Transform 30 g of FeBr3 in grams:
30 / 296.6 = 0.10 mole
Transform 20.3 g of Fe2(CrO4)3 in grams:
20.3 / 459.7 = 0.0442
You have an excess of Fe2(CrO4)3, the limiting reagent is FeBr3.
