Respuesta :
Two teams are pulling a heavy chest, located at point X,The teams are 4. 6 meters away from each other , ,The equation can be used to solve for angle A by Law of Sine Here according to the questions the missing angles are ∠A=40.82° and ∠B=29.36°.
Given:-
- Team A is 2. 4 meters away from the chest.
- Team B is 3. 2 meters away from the chest.
- At angle 110° rope is attached.
- A X B = 110 degrees.
- The length of angle X B = 3.
- The length of angle AX = 2.4.
To find the equation can be used to solve for angle A we will check for the given two angles by applying Law of sine,
In the following diagram the values are as follows:-
[tex]\rm Angles\;as\;follows\\ \angle A = not \;given\\\angle B = not \;given\\\angle C = 110°\\\\\Sides\; as\; follow\\a = 3.2 unit\\b = 2.4 unit\\c = 4.6 unit[/tex]
We will now solve for ∠B,
[tex]\rm \dfrac{\sin C}{c} = \dfrac{sin B }{b}\\\rm \dfrac{\rm sin 110}{ 4.6} = \dfrac{\rm sin B}{2.4}\\sin B = 2.4\times \dfrac{\sin110}{4.6}\\\sin B = 29.36\textdegree[/tex]
Again we will solve for ∠A.
[tex]\rm \dfrac{\sin C}{c} = \dfrac{sin A }{a}\\\\\rm \dfrac{\rm sin 110}{ 4.6} = \dfrac{\rm sin A}{3.2}\\\\sin A = 3.2 \times \dfrac{\sin110}{4.6}\\\\\sin B = 40.82\textdegree[/tex]
Therefore,The equation can be used to solve for angle A by Law of Sine the missing angles are ∠A=40.82° and ∠B=29.36°.
Learn more about Sine Law here : https://brainly.com/question/4058712
