The angle of each lettered angle are as follows;
a = 128°
b = 128°
c = 52°
d = 76°
e = 104°
f = 104°
g = 76°
h = 52°
j = 70°
k = 70°
l = 40°
m = 110°
n = 58°
The angles of the triangle can be solved as follows:
- a = 180 - 52 = 128°(angles on a straight line)
- b = a Therefore, b = 128°(alternate angles)
- c = 52° (alternate exterior angles)
- d = 180 - 52(2) = 76° (base of isosceles triangle)
- e = 180 - d(76°) = 104° (corresponding angles and angles on a straight line principle )
- f = e, therefore, f = 104° (alternate angles)
- g = 76° (angle on a straight line, alternate angle and vertical angles were applied)
- h = 104 / 2 = 52°
- j = 70°
- k = j. Therefore, k = 70° (alternate angles)
- m = 180 - 70 = 110°(angle on a straight line)
- l = 180 - 70 - 70 = 40°(sum of angles in a triangle)
- n = 180 - 52 - 70 = 58° (sum of angles in a triangle)
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