starboy653521
starboy653521 starboy653521
  • 26-01-2022
  • Mathematics
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[tex]\footnotesize \displaystyle \bold {\int_{[0, \frac{\pi}{8} ] \cup[ \frac{3 \pi}{8}, \frac{\pi}{2}]} \: \frac{dx}{ \sqrt{1 - sin2x} } }[/tex]
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sam69987667765 sam69987667765
  • 27-01-2022

[tex]\footnotesize \displaystyle \bold {\int_{[0, \frac{\pi}{8} ] \cup[ \frac{3 \pi}{8}, \frac{\pi}{2}]} \: \frac{dx}{ \sqrt{1 - sin2x} } }[/tex]

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