Respuesta :
Using the Poisson distribution, it is found that there is a 0.8647 = 86.47% probability of at least one flaw appearing in 300 square feet.
What is the Poisson distribution?
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
- x is the number of successes
- e = 2.71828 is the Euler number
- [tex]\mu[/tex] is the mean in the given interval.
Flaws in a certain type of drapery material appear on the average of one in 150 square feet, hence, considering 300 square feet, the mean is of:
[tex]\mu = \frac{300}{150} \times 1 = 2[/tex]
The probability of at least one flaw appearing in 300 square feet is given by:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1353[/tex]
Then:
[tex]P(X \geq 1) = 1 - 0.1353 = 0.8647[/tex]
0.8647 = 86.47% probability of at least one flaw appearing in 300 square feet.
More can be learned about the Poisson distribution at https://brainly.com/question/13971530
