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If a skateboarder skates down a ramp for 3 seconds,and his initial velocity was 0.8 m/s and his final velocity was 7 m/s.Then what was his acceleration.

Respuesta :

samuelonum1

Newtons First Equation of motion can be applied and plugin in the given data the acceleration was found to be 2.03 m/s^2

Velocity, Acceleration and Time

Given Data

Time t= 3 seconds

Initial Velocity u = 0.8 m/s

Final Velocity v = 7 m/s

Acceleration a = ??

Applying the Newton's First equation of motion

v = u+at--------------1

Substituting our given Data

7 = 0.8+a*3

solving for acceleration a

7-0.9 = 3a

6.1 = 3a

divide both sides by 3 we have

a = 6.1/3

a = 2.03 m/s^2

Answer a = 2.03 m/s^2

Learn more about equations of motion here:

https://brainly.com/question/25951773

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