Suppose that the mean daily viewing time of television is 8. 35 hours. Use a normal probability distribution with a standard deviation of 2. 5 hours to answer the following questions about daily television viewing per household.

Respuesta :

The probability that a household views television between 5 and 10 hours a day is :  0.6553

Given data :

mean daily viewing time ( μ ) = 8.35 hours

standard deviation ( σ ) = 2.5 hours

Determine the probability of a household view btw 5 and 10 hours a day

P ( 5 ≤ x ≤ 10 )

= P ((5 - 8.35 )/2.5 < z < ( 10 - 8.35 )/2.5)

= P ( -1.34 < z < 0.66 )

Therefore the probability  P ( 5 ≤ x ≤ 10 )  becomes

P( z < 0.66 ) - P ( z < -1.34 )

= 0.7454 - 0.0901   ( applying normal tables )

= 0.6553

Hence we can conclude that The probability that a household views television between 5 and 10 hours a day is :  0.6553

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What is the probability that a household views television between 5 and 10 hours a day