Respuesta :
Answer:
molar mass of CaCO3=40+12+3(16)
=100 gmol-1
Ca percent composition=40/100*100%
=40%
C percent composition=12/100*100%
=12%
0 percent composition=48/100*100%
=48%
Answer:
Since we're sticking with theoretical values instead of experimental, Percent Composition would be (Molar Mass of the element) / (Molar mass of compound) x 100%
Molar mass of Calcium: 40g/mol
Molar mass of Carbon: 12g/mol
Molar mass of Oxygen: 16g/mol
Molar mass of CaCO3 (Calcium Carbonate) = (40) + (12) + (16)*3 = 100g/mol
Percentage composition of Calcium = [tex]\frac{40}{100} \ * \ 100 =[/tex] 40% of Calcium
Percentage composition of Carbon = [tex]\frac{12}{100} \ * \ 100 =[/tex] 12% of Carbon
(For the next one, there are 3 oxygen, so it'd be 16x3 = 48g/mol)
Percentage composition of Oxygen = [tex]\frac{48}{100} \ * \ 100 =[/tex] 48% of Oxygen