The climb angle (angle of elevation) of an airplane taking off is 20°. If the airplane maintains that angle until it reaches cruising altitude, what is the approximate horizontal
ground distance from that airplane to the point of takeoff when the airplane has reached its cruising altitude of 30,000 feet? (Remember that 1 mile = 5280 feet) 107 miles ground distance from that airplane to the point of takeoff when the airplane has reached its cruising altitude of 30,000 feet?

The approximate horizontal ground distance from airplane to the point of takeoff when the airplane has reached its cruising altitude of [tex]30,000[/tex] feet is [tex]107[/tex] miles.

What is horizontal ?

Horizontal is a straight line that goes from left to right or right to left.

What is altitude ?

Altitude or height is a distance measurement, in the vertical or "up" direction, between a reference datum and a point or object.

We have,

Angle of elevation of an airplane taking off [tex]= 20^{0}[/tex]

Ground distance from airplane to the point of takeoff [tex]=x[/tex] miles

And

[tex]1[/tex] mile [tex]=5280[/tex] feet

So,

According to question;

Ground distance from airplane to the point of takeoff ;

[tex]tan 20^{0} = \frac{Altitude}{Horizontal Distance}[/tex]

[tex]tan20^{0} = \frac{30000}{Horizontal Distance}[/tex]

Horizontal Distance [tex]= 107[/tex] miles

Hence, we can say that The approximate horizontal ground distance from airplane to the point of takeoff when the airplane has reached its cruising altitude of [tex]30,000[/tex] feet is [tex]107[/tex] miles.

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