As shown below, if M = 6.0 kg, what is the tension in the
connecting string? The pulley and all surfaces are frictionless.
30°

Respuesta :

The tension in the connecting string is 14.7 N.

Net force of the masses

The net force of the masses is calculated as follows;

[tex]F_{net} = Mgsin(\theta)+ Mg[/tex]

Acceleration of the masses

The acceleration of the masses is calculated as follows;

[tex]a = \frac{F_{net}}{M+ M} = \frac{M(gsin\theta + g)}{2M} = \frac{gsin\theta + g}{2} \\\\a = \frac{9.8sin(30) \ + \ 9.8}{2} = 7.35 \ m/s^2[/tex]

Tension in the connecting string

The tension in the connecting string is calculated as follows;

[tex]mg - T = ma\\\\T = mg - ma\\\\T = m(g - a)\\\\T = 6(9.8 - 7.35)\\\\T = 14.7 \ N[/tex]

Thus, the tension in the connecting string is 14.7 N.

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