❖Question :
[tex]\\[/tex]
The length rectangle is 7.1 cm and it's breadth is 2.5 cm. Find area and perimeter.
[tex]\\[/tex]
❖Given:
[tex]\\[/tex]
Length of rectangle = 7.1 cm
Breadth of rectangle = 2.5 cm
[tex]\\[/tex]
❖ To find:
[tex]\\[/tex]
Area of rectangle
Perimeter of rectangle
[tex]\\[/tex]
❖ Solution:
[tex]\\[/tex]
Part 1 :‐
To find area of rectangle
[tex]\\[/tex]
we know:
Area of rectangle = Length × Breadth
[tex]\\[/tex]
So:-
↣Area of rectangle = Length × Breadth
[tex]\\[/tex]
↣Area of rectangle = 7.1 × 2.5 (cm × cm)
[tex]\\[/tex]
↣Area of rectangle = 7.1 × 2.5 cm²
[tex]\\[/tex]
↣Area of rectangle =( 71 × 25 )/100cm²
[tex]\\[/tex]
↣Area of rectangle =( 71 × 25 )/(25 × 4)cm²
[tex]\\[/tex]
↣Area of rectangle =( 71 × 1)/(1 × 4)cm²
[tex]\\[/tex]
↣Area of rectangle = 71/4cm²
[tex]\\[/tex]
↣Area of rectangle = 17.75 cm²
[tex]\\[/tex]
Part 2 :‐
Part 2 :‐To find perimeter of rectangle
[tex]\\[/tex]
we know:
Perimeter of rectangle =2( Length + Breadth )
[tex]\\[/tex]
So:-
[tex]\\[/tex]
↣Perimeter of rectangle =2( Length + Breadth )
[tex]\\[/tex]
↣Perimeter of rectangle =2( 7.1 + 2.5 )cm
[tex]\\[/tex]
↣Perimeter of rectangle =2( 9.6) cm
[tex]\\[/tex]
↣Perimeter of rectangle =2 × 9.6 cm
[tex]\\[/tex]
↣Perimeter of rectangle = 19.6 cm
[tex]\\[/tex]
━━━━━━━━━━━━━━━━
[tex] \\[/tex]
✎ᝰ Cheers! all done :)
Answer:
Step-by-step explanation:
In the question we're given ,
And we are asked to find ,
We know that ,
[tex] \longmapsto \: \pink{\boxed{\sf{Area \: of \: rectangle = l \times b}}} [/tex]
Where ,
So substituting values :
[tex] \hookrightarrow \: 7.1 \times 2.5[/tex]
Multiplying 7.1 and 2.5 :
[tex] \hookrightarrow \: \blue{\boxed{ \bold{17.75 \: cm {}^{2} }}}[/tex]
We know that ,
[tex] \longmapsto \: \pink{\boxed{ \sf{Perimeter \: of \: rectangle = 2 ( l + b )}}}[/tex]
Where ,
So substituting values :
[tex] \hookrightarrow \: 2(7.1 + 2.5)[/tex]
Solving parenthesis by adding 7.1 and 2.5 :
[tex] \hookrightarrow \: 2(9.6)[/tex]
Multiplying 2 and 9.6 :
[tex] \hookrightarrow \: \blue{\boxed{\bold{19.2 \: cm}}}[/tex]
