A line contains the points R (-5, -6) S (1, 5) and T (x, 10). Solve for x. Be sure to show and explain all work. ( How did this person get this answer?

By finding the line and evaluating, we will see that x = 41/11
First, we need to get the line, for a line that passes through two points (x₁, y₁) and (x₂, y₂) the slope is:
[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
So here we use the points (-5, -6) and (1, 5), the slope will be:
a = (5 - (-6))/(1 - (-5) = 11/6
So the line is something like:
y = (11/6)*x + b
To get the value of b, we use one of the given points, for example if we use the second point we must have:
5 = (11/6)*1 + b
5 - 11/6 = b
30/6 - 11/6 = b
19/6 = b
So the line is:
y = (11/6)*x + 19/6
Now, to find the value of x, we replace y by 10:
10 = (11/6)*x + 19/6
60/6 - 19/6 = (11/6)*x
41/6*(6/11) = x = 41/11
So the person in the image got it correct, but with other method.
If you want to learn more about linear equations, you can read:
https://brainly.com/question/4074386
Lines are colinear so slopes must be equal