Answer:
[tex]\boxed{\sf{8w-3}}[/tex]
Step-by-step explanation:
This problem can be solved by using the distributive property of left-to-right numbers.
[tex]\underline{\text{Distributive Property}}[/tex]
A(B+C)=AB+AC
4(2w+2)-11
4(2w+2)
Multiply by 2.
4*2=8
4*2=8
Rewrite the problem down.
8w+8
8w+8-11
Then, subtract.
8-11=-3
Rewrite the problem down.
8w-3
Therefore, the final answer is 8w-3.
I hope this helps you! Let me know if my answer is wrong or not.
