A cellular phone and its case together costs php 25,500. If the cellular phone costs php 24,050 more than the case, how much does the case cost?.

Respuesta :

The case costs php 725

Word Problem in Mathematics.

Let the cost of the case be represented as x

and the cost o of cellular phone be 24,050 + x

Such that both cellular phone and its case together costing php 25,500

can be mathematically represented as

case +cellular phone =25,500.

Solving, We have

x +24,050 + x=25,500.

2x =25,500-24,050

x =1,450/2

x=725

Therefore the case costs php725

and the cellular phone cost 24,050 + 725 =php 24,775

Learn more on similar Word problem here: https://brainly.com/question/75685