contestada

After the collision, the first cart is observed moving away from the second at a velocity of v/2. How much impulse did the second cart transfer to the first

Respuesta :

asuwafohjames

The impulse transferred to the first cart by the second cart is 3mv/2 kgm/s.

What is impulse?

Impulse can be defined as the product of the mass and the change in velocity of a  body.

The impulse transferred to the first cart by the second cart can be calculated using the formula below.

Formula:

  • I = m(v-u)............... Equation 1

Where:

  • I = Impulse transferred to the first cart by the second cart
  • m = mass of the first cart
  • v = Final velocity of the first cart
  • u = Initial velocity of the first cart.

From the question,

Given:

  • m = m kg
  • v = v m/s
  • u = -v/2 m/s (moving away)

Substitute these given data into equation 1

  • I = m[v-(-v/2)]
  • I = m(v+v/2)
  • I = m(3v/2)
  • I = 3mv/2 kgm/s

Hence, the impulse transferred to the first cart by the second cart is 3mv/2 kgm/s.
Learn more about impulse here: https://brainly.com/question/20586658


Complete question: consider two carts moving on a track. the first cart has a mass of m, and the second has a mass of 3m. the first mass is moving at a velocity v towards the second, which is stationary. after the collision, the first cart is observed moving away from the second at a velocity of v/2. how much impulse did the second cart transfer to the first?

Otras preguntas