Find an equation of the circle that has center (-2, 6) and passes through (6, 2)

Please help! I’ve tried looking for the answer and trying to solve the problem but none of the answers I’ve done are right. I need to get this question right so it’s be much appreciated if you helped me out. Thank you so much and have a great day!

Respuesta :

Answer:

(x+2)^2+(y-6)^2=80

Step-by-step explanation:

equation of a circle : [tex](x-a)^{2} +(y-b)^{2}=r^2\\[/tex]

where (a,b) is the center and r is the radius

r = distance between two points

r = [tex]\sqrt{(6-(-2))^2+(2-6)^2} =\sqrt{8^2+(-4)^2} =\sqrt{64+16} =\sqrt{80}[/tex]

equation of the circle = [tex](x+2)^2+(y-6)^2=80[/tex]