hebaarif2007
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pls help
1.P = 3a + 3b
Make a the subject of the formula.
2.Make a the subject of v = u + at
3.Make x the subject of 5x + 6y + 12 = 0
4.Make b the subject of A = 3b + 9
5.Make x the subject of y = 2/5x – 12

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fieryanswererft

given sample: P = 3a + 3b, make a subject

  • [tex]P = 3a + 3b[/tex]
  • [tex]P - 3b = 3a[/tex]
  • [tex]a = \frac{P-3b}{3}[/tex]

given sample: v = u + at, make a subject

  • [tex]v = u + at[/tex]
  • [tex]v - u = at[/tex]
  • [tex]a = \frac{v-u}{t}[/tex]

given sample: 5x + 6y + 12 = 0, make x subject

  • [tex]5x + 6y + 12 = 0[/tex]
  • [tex]5x = - 12 - 6y[/tex]
  • [tex]x = \frac{- 12 - 6y}{5}[/tex]

given sample: A = 3b + 9, make b subject

  • [tex]A = 3b + 9[/tex]
  • [tex]A -9= 3b[/tex]
  • [tex]\frac{A -9}{3} = b[/tex]

given sample: y = 2/5x – 12, make x subject

  • [tex]y = \frac{2}{5} x - 12[/tex]
  • [tex]y +12= \frac{2}{5} x[/tex]
  • [tex]\frac{5(y+12)}{2} =x[/tex]
  • [tex]\frac{5y+60}{2} =x[/tex]
Hi1315

Answer:

1)  [tex]\frac{(P -3b)}{3} = a[/tex]

2)  [tex]\frac{(v-u)}{a} =t[/tex]

3) [tex]x = \frac{( -12-6y)}{5}[/tex]

4)  [tex]\frac{(A-9)}{3} =b[/tex]

5) [tex]\frac{5(y+12)}{2} =x[/tex]

Step-by-step explanation:

1) P = 3a + 3b

First, take 3b to the left side.

P - 3b = 3a

Divide both sides by 3.

[tex]\frac{(P -3b)}{3} = a[/tex]

2)  v = u + at

First, take u to the left side.

v - u = at

Divide both sides by a.

[tex]\frac{(v-u)}{a} =t[/tex]

3) 5x + 6y + 12 = 0

First, take 12 to the right side.

5x + 6y = -12

Take 6y to the right side.

5x = -12 - 6y

Divide both sides by 5.

[tex]x = \frac{( -12-6y)}{5}[/tex]

4) A = 3b + 9

First, take 9 to the left side.

A - 9 = 3b

Divide both sides by 3.

[tex]\frac{(A-9)}{3} =b[/tex]

5) y = 2/5x – 12

First, take -12 left side.

y + 12 = 2 / 5x

Multiply both sides by 5.

5 ( y + 12 ) = 2x

Divide both sides by 2.

[tex]\frac{5(y+12)}{2} =x[/tex]

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