Answer:
0.1 moles of N2 will react with 0.3034 moles of Mg.
Explanation:
[tex]\sf{balanced \ eqaution = 3Mg + N2 \rightarrow Mg3N2}[/tex]
using molar ratio:
3Mg : N2
3 : 1
moles of N2:
[tex]\hookrightarrow \sf\frac{0.3034 }{3} *1[/tex]
[tex]\hookrightarrow \sf 0.10113 \ moles \ of \ N2[/tex]