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In an experiment, 200.00 grams of Al2O3 was decomposed producing 77.18 grams of Al. Calculate the percent yield for this experiment?

Respuesta :

Answer:

Explanation:

Molecular weight of Al: 27

Molecular weight of O: 16

Percentage composition of Al by weight in Al2O3

= (27*2) / (27*2 + 16*3)

= 0.5294

In 200 grams of Al2O3, there are

= 200*0.5294

= 105.88 grams of Al

77.18 grams of Al was produced in the experiment.

Percent yield for the experiment

= product mass / reactant mass * 100%

= 77.18 / 105.88 * 100%

= 72.89%

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