Using the normal distribution, it is found that the minimum table clearance required to satisfy the requirements of fitting 95% of men is of 23.6 in.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem, for men's knee heights, we have that:
The 95th percentile is X when Z has a p-value of 0.95, so X when Z = 1.645, then:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.645 = \frac{X - 21.8}{1.1}[/tex]
[tex]X - 21.8 = 1.1(1.645)[/tex]
[tex]X = 23.6[/tex]
The minimum table clearance required to satisfy the requirements of fitting 95% of men is of 23.6 in.
More can be learned about the normal distribution at https://brainly.com/question/24663213