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A source of ultrasound emits waves at a frequency of 2.00×106 Hz . The waves are reflected by red blood cells moving toward the source at a speed of 0.30 m/s

Determine the difference between the frequency of sound detected at a receiver next to the source and the source sound frequency fs . The speed of sound in the blood is 1500.00 m/s .

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onyebuchinnaji

The difference between the source frequency and the observed frequency is 400 Hz.

Doppler effect

The observed frequency or frequency of sound detected is calculated by applying Doppler effect formula;

[tex]f_s = f_0(\frac{v}{v - v_s} )\\\\2\times 10^6 = f_0 (\frac{1500}{1500 - 0.3} )\\\\2\times 10^6 = 1.0002 f_o\\\\f_o = \frac{2\times 10^{6}}{1.0002} \\\\f_o = 1.9996 \times 10^6 \ Hz[/tex]

Difference between the source frequency and the observed frequency

[tex]f_s - f_o = 2\times 10^6 \ Hz \ - \ 1.9996 \times 10^6 \ Hz = 400 \ Hz[/tex]

Learn more about Doppler effect here: https://brainly.com/question/3841958

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