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Given :
[tex] \\ [/tex]
To find:
[tex] \\ [/tex]
[tex] \\ [/tex]
Solution:-
[tex] \\ [/tex]
We know:-
[tex] \rm circumference = 2\pi r[/tex]
[tex] \\ \\ [/tex]
So:-
[tex] \looparrowright \sf circumference = 2\pi r[/tex]
[tex] \\ [/tex]
[tex] \looparrowright \sf 29.8= 2\pi r[/tex]
[tex] \\ [/tex]
[tex] \looparrowright \sf 29.8= 2 \times \dfrac{22}{7} \times r[/tex]
[tex] \\[/tex]
[tex] \looparrowright \sf \dfrac{298 \times7}{22 \times 2 \times 10} = r[/tex]
[tex] \\ \\ [/tex]
[tex] \looparrowright \sf \dfrac{149 \times7}{22 \times 10} = r[/tex]
[tex] \\ \\ [/tex]
[tex] \looparrowright \sf \dfrac{1043}{220} = r[/tex]
[tex] \\ [/tex]
[tex] \looparrowright \sf r = 4.74[/tex]
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