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Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid. What is the distance, in units, between the points Ralph plotted?
Enter your numerical answer in the box, do not include words or spaces.

Respuesta :

Nonportrit

Answer:

6 units

Step-by-step explanation:

Given the following question:

Point A = (-4, 3) = (x, y)
Point B = (-4, -3) = (x, y)

To find the distance between the following points we must first plot the points on the coordinate plane.

Point A: Move over to the left four times, move up three times.
Point B: Move over to the left four times, move down three times.

The distance between the two points given is "six units." Since the x values are the same, and the y values are opposites from each other doubling their distance by two.

Hope this helps.

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KlareMontefalco

DISTANCE

❖ Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid. What is the distance, in units, between the points Ralph plotted? (Enter your numerical answer in the box, do not include words or spaces.)

Answer:

  • [tex] \color{hotpink} \bold{6 \: units}[/tex]

— — — — — — — — — —

Formula:

- To get the distance between two points, we may use formula

  • [tex] \underline{ \boxed{d = \sqrt{( x_{2} - x_{1}) {}^{2} + (y_{2} - y_{1}) {}^{2} } }}[/tex]

Given:

Since Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid then, the givens are...

  • [tex] \: \: \: \: \: \: \: x_{1} = - 4 \: \: \: \: \:\: \: \: \: \: \: \: \: y_{1} = 3\\ \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: y_{2} = - 3[/tex]

Solution:

  • [tex]d = \sqrt{( x_2- x_{1}) {}^{2} + (y_{2} - y_{1}) {}^{2} }[/tex]

  • [tex]d = \sqrt{[-4-(-4)]²+(-3-3)²}[/tex]

  • [tex]d = \sqrt{(0)²+(-6)²}[/tex]

  • [tex]d = \sqrt{0+36}[/tex]

  • [tex]d = \sqrt{36}[/tex]

  • [tex]d = \blue{6}[/tex]

Therefore, the distance between two given points is 6.

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