What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series to write the formula unit equation!)

For the answer to the question above,
The reaction of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is

Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s)

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Tringa0 Tringa0 · Answer 2 · 2019-11-28T06:53:01+01:00

Answer:

The net ionic equation for the reaction of solid iron with aqueous copper sulfate:

[tex]Fe(s)+Cu^{2+}(aq)\rightarrow Fe^{2+}+(aq)+Cu(s)[/tex]

Explanation:

Solid iron = Fe

Copper sulfate = [tex]CuSO_4[/tex]

[tex]Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)[/tex]

In an aqueous solution of copper sulfate we have copper (II) ions and sulfate ions.

[tex]CuSO_4(aq)\rightarrow Cu^{2+}(aq)+SO_4^{2-}(aq)[/tex]

In an aqueous solution of ferrous sulfate we have ion (II) ions and sulfate ions.

[tex]FeSO_4(aq)\rightarrow Fe^{2+}+(aq)+SO_4^{2-}(aq)[/tex]

[tex]Fe(s)+Cu^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Fe^{2+}+(aq)+SO_4^{2-}(aq)+Fe^{2+}+(aq)[/tex]

Cancelling out the common ions from both sides, we get the net ionic equation:

[tex]Fe(s)+Cu^{2+}(aq)\rightarrow Fe^{2+}+(aq)+Cu(s)[/tex]