Simplify 5 log2 k − 8 log2 m + 10 log2 n.
A. 7 log2 (k − m + n)
B. 7 log2 kn over m
C. log2 50 kn over 8 m
D. log2 k to the fifth power n to the tenth power/ m to the eighth power
The numerical coefficients of the logarithm are originally, the exponents of the variables. Such that, log₂k⁵ - log₂m⁸ + log₂n¹⁰ Then the addition means we multiply them and subtraction means divide. The final answer would be, log (k⁵n¹⁰/m⁸)
