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How much greater is the area of a a square with a side length of 8 inches than the area of a circle with radius of 4 inches?

Respuesta :

Moskid
Area of a square= l²
                           = 8×8 = 64 in²

Area of  a circle= πr²
                         = π × 4²
                         = 50.3 in²
Difference = 64 - 50.3 = 13.7 in²

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