With the Hubble's constant H₀, the estimated age of the universe would be:
T = 8,332,452,617.49 years.
We know that the age of the universe is something near to the time the galaxies needed to reach their current distance:
T = D/V
And by Hubble's law, we know that:
V = H₀*D
Then we can write:
T = D/(H₀*D) = 1/H₀
So, we can say that the age of the universe is something near the inverse of Hubble's constant.
Then we have:
T = 1/(36 km/s*Mly) = (1/36) s*Mly/km
Now we need to perform the correspondent change of units.
1 Mly = 1 million light-years
Such that:
1 ly = 9.461*10^12 km
Then 1 million light-years over km is equal to:
1 Mly/km = 1,000,000*(9.461*10^12 km)/km = 9.461*10^18
Then we can replace it:
T = (1/36) s*Mly/km = (1/36)*9.461*10^18 s
T = 2.628*10^17 s
This is the age in seconds, but we want it in years.
We know that:
1 year = 3.154*10^7 s
Then to change the units, we compute:
T = (2.628*10^17 s/3.154*10^7 s)* 1 yea
T = 8,332,452,617.49 years.
If you want to learn more about Hubble's constant, you can read:
https://brainly.com/question/9770981
