A theater has 15 seats in the front row. The number of seats in each row follows an arithmetic series with 72 seats in the last row. The theater has a total of 870 seats. How many rows does the theater have? By how many seats does each row increase? Please show all work.

Respuesta :

Step-by-step explanation:

Given:

Theater has 15 seats

Last Row has 72 seats.

Theater has a total of 870 seats.

Unknown: Number of rows

Number of seats in each row.

Equations: Since we know the total number of seats the Theater has we can use the sum of arithmetic series

[tex]s = \frac{a _{1} + a _{n} }{2} n[/tex]

Where a1 is the first row of seats

s is total number of seats

an is last row of seats

n is number of rows.

[tex]870 = \frac{15 + 72}{2} (n)[/tex]

[tex]870 = \frac{87}{2} n[/tex]

[tex]2(870) = 87n[/tex]

[tex]20 = n[/tex]

So we have 20 rows.

To find how many seats does each row increase, we use this formula,

[tex]a _{n} = a + (n - 1)d[/tex]

Let use the 20th row as an example,

[tex]a _{20} = 15 + (19)d[/tex]

[tex]72 = 15 + (19)d[/tex]

[tex]57 = 19d[/tex]

[tex]3 = d[/tex]

So the common difference is 3.

So the seats of each row increase by 3.