Imagine that 64% of the people living in a remote village in the mountains can taste phenylthiocarbamide (ptc). In order to taste ptc, you must have at least one copy of the dominant ptc taster allele. If the population were in hardy-weinberg equilibrium for the ptc gene, calculate the allele and genotype frequencies as listed below:

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22-03-2022
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Imagine that 64% of the people living in a remote village in the mountains can taste phenylthiocarbamide (ptc). In order to taste ptc, you must have at least one copy of the dominant ptc taster allele. If the population were in hardy-weinberg equilibrium for the ptc gene, calculate the allele and genotype frequencies as listed below:

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luisvaschetto luisvaschetto · Answer 1 · 2022-03-30T11:56:08+02:00

If the population were in Hardy-Weinberg equilibrium then the frequency of heterozygous will be 0.48, recessive homo-zygous 0.36 and dominant homo-zygous 0.16.

What is the Hardy-Weinberg equilibrium?

The Hardy-Weinberg equilibrium is a model used in population genetics to estimate genotypic and allele frequencies.

The Hardy-Weinberg equilibrium is p2 + 2pq + q2 = 1. In this case, p2 + 2pq is equal to 0.64.

In consequence, q2 = 1 – 0.64 = 0.36 >> q is equal to 0.6 and p = 1 – 0.6 = 0.4.

Finally, the frequency of heterozygous is 2pq (2 x 0.4 x 0.6) = 0.48, recessive homo-zygous is 0.36 and dominant homo-zygous is 0.16 (1 - 0.48 - 0.36 = 0.16).

Learn more about the Hardy-Weinberg equilibrium here:

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