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PLEASE ANSWER (100points)
When evaluating (6 x + 9) squared minus 5 for x = 1, the given value of 1 is substituted for what part of the expression?
the exponent
the constant
the variable
any numerical value

Respuesta :

semsee45

Answer:

the variable

Step-by-step explanation:

Given expression:

[tex](6x+9)^2-5[/tex]

When evaluating the expression for [tex]x=1[/tex], we need substitute 1 for the variable ([tex]x[/tex]) in the expression.

Evaluating the expression for [tex]x=1[/tex]:

[tex]\implies (6\cdot1+9)^2-5[/tex]

[tex]\implies (6+9)^2-5[/tex]

[tex]\implies (15)^2-5[/tex]

[tex]\implies 225-5[/tex]

[tex]\implies 220[/tex]

Answer:

Variable

  • As variable is x and we have to substitute x=1

Step-by-step explanation:

Let's find the value

[tex]\\ \rm\Rrightarrow (6x+9)^2-5[/tex]

[tex]\\ \rm\Rrightarrow (6+9)^2-5[/tex]

[tex]\\ \rm\Rrightarrow 14^2-5[/tex]

[tex]\\ \rm\Rrightarrow 196-5[/tex]

[tex]\\ \rm\Rrightarrow 191[/tex]

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