The concentration, in grams per liter, of a solution prepared by dissolving 0.00040 mol HCl in 2.2L H₂O is 0.0066 g/L.
Mass of any substance will be calculated by using their moles as:
n = W/M, where
W = required mass
M = molar mass
GIven moles of HCl = 0.00040 mole
Mass of 0.00040 mole of HCl will be calculated as:
W = (0.00040mol)(36.45g/mol) = 0.01458g
Given volume of Water = 2.2 L
Now the concentration in molality (g/L) will be calculated as:
concentration = (0.01458g) / (2.2L) = 0.0066 g/L.
Hence required concentration is 0.0066 g/L.
To know more about molality, visit the below link:
https://brainly.com/question/9149034