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Find the value of
[tex]\mathsf{\theta=tan^{-1}\bigg(\dfrac{\sqrt{3}}{3}\bigg)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}}[/tex]
So that means
[tex]\mathsf{tan\,\theta=\dfrac{\sqrt{3}}{3}}\\\\\\
\mathsf{tan\,\theta=tan\,\dfrac{\pi}{6}}\\\\\\\\
\therefore~~\mathsf{\theta=\dfrac{\pi}{6}}\quad\Rightarrow\quad
\boxed{\begin{array}{c}
\mathsf{tan^{-1}\bigg(\dfrac{\sqrt{3}}{3}\bigg)=\dfrac{\pi}{6}}
\end{array}}[/tex]
I hope this helps. =)
Tags: inverse tangent function tan arctan trigonometry trig
