Respuesta :
The Margin of error is 0.3 when assuming a 90% confidence level.
It is given that among 320 randomly selected airline travelers, the mean number of hours spent traveling per year is 24 hours and the standard deviation is 2.9.
It is required to find the margin of error when the confidence level is 90%.
What is the margin of error(MOE)?
It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.
The formula for finding the MOE:
[tex]\rm MOE= Z_{score}\times\frac{s}{\sqrt{n}}[/tex]
Where [tex]\rm Z_{score}[/tex] is the z score at the confidence interval
s is the standard deviation
n is the number of samples.
We have in the question:
[tex]\rm Z_{score}[/tex] at 90% confidence interval = 1.645 (From the Z score table)
s = 2.9
n = 320
Put the above values in the formula, we get:
[tex]\rm MOE= 1.645\times\frac{2.9}{\sqrt{320}}[/tex]
MOE = 0.2666
Rounding the nearest tenth:
MOE = 0.3
Thus, The Margin of error is 0.3 when assuming a 90% confidence level.
Learn more about the Margin of error here:
https://brainly.com/question/13990500
