The volume of an ideal gas at a constant temperature is 5.0L. The gas is held under a
pressure of 0.89 atm. If the pressure is increased to 1.32 atm, what is the volume in
ml.?

Respuesta :

At constant temperature, The final volume of the ideal gas after the pressure increment is 3370ml.

Given the data in the question;

  • Initial volume of the ideal gas; [tex]V_1 = 5.0L[/tex]
  • Initial Pressure; [tex]P_1 = 0.89atm[/tex]
  • Final Pressure; [tex]P_2 = 1.32atm[/tex]
  • Final volume of the ideal gas; [tex]V_2 = \ ?[/tex]

Boyle's law

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P at constant temperature.

It is expressed as;

[tex]P_1V_1 = P_2V_2[/tex]

Where [tex]P_1[/tex] is Initial Pressure, [tex]V_1[/tex] Initial volume, [tex]P_2[/tex] is Final Pressure and [tex]V_2[/tex] is Final volume.

To determine the final volume of the gas, we substitute our given values into the expression above.

[tex]P_1V_1 = P_2V_2\\\\V_2 = \frac{P_1V_1}{P_2}\\ \\V_2 = \frac{0.89atm\ *\ 5.0L }{1.32atm} \\\\V_2 = \frac{0.89\ *\ 5.0L }{1.32}\\\\V_2 = \frac{ 4.45L }{1.32}\\\\V_2 = 3.37L\\\\V_2 = 3370ml[/tex]

Therefore, at constant temperature, the final volume of the ideal gas after the pressure increment is 3370ml.

Learn more about Boyle's law: https://brainly.com/question/1437490