At a constant temperature, a 4.50 L container of helium is held under 100 kPa. The
helium is transferred to a larger container (7.0 L), what is the new pressure?

Respuesta :

If a 4.50 L container of helium is held under 100 kPa and a larger container (7.0 L), the new pressure  is mathematically given as

P=67.28kpa

What is a new pressure?

Question Parameter(s):

At a constant temperature, a 4.50 L container of helium is held under 100 kPa.

The helium is transferred to a larger container (7.0 L),

Generally, the equation for the Ideal gas  is mathematically given as

V1P1=V2P2

Therefore

4.50*100=7.0*P2

P=450/7

P=67.28kpa

In conclusion, the new pressure is

P=67.28kpa

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